---
author: "Devoalda"
authorEmoji: 🐺
title: "Leetcode - Defanging an IP Address (1108)"
date: 2023-02-12T08:00:54+08:00
description: Leetcode Problem 1108
draft: false
hideToc: false
enableToc: true
enableTocContent: true
tocPosition: inner
tocLevels: ["h1", "h2", "h3"]
libraries:
  - mathjax
tags:
  - Java
  - Leetcode
series:
  - Leetcode
categories:
  -
image:
---

# Introduction

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

## Input and Output

Example 1:

```
Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"
```

Example 2:

```
Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"
```

## Process

I've rarely done string replacement using Java, but upon looking around the internet
for some resources, I found the `.replaceAll()` method that replaces characters in a string.

Using this method, I was able to replace the `.`s in the given IP to `[.]`

# Code

```java
class Solution {
    public String defangIPaddr(String address) {
        address = address.replaceAll("\\.", "[.]");
        return address;

        // One liner
        // return address.replaceAll("\\.", "[.]");
    }
}
```

# Afterthoughts

This is a simple challenge, I'll probably try it with other languages in the near future